United States presidential election in Vermont, 1860
Main article: United States presidential election, 1860
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The 1860 United States presidential election in Vermont took place on November 2, 1860 throughout all 33 states which was part of the 1860 United States presidential election. Voters chose five electors of the Electoral College, who voted for President and Vice President.
Vermont was the birth state of Northern Democratic presidential candidate Stephen A. Douglas.
Republican candidate Abraham Lincoln won by about 50 percentage points.
Results
Presidential Candidate | Party | Electoral Vote (EV) | Popular Vote | Percentage |
---|---|---|---|---|
Abraham Lincoln | Republican | 5 | 33,808 | 75.7% |
Stephen A. Douglas | Northern Democratic | 0 | 8,649 | 19.4% |
John Bell | Constitutional Union | 0 | 1,969 | 4.4% |
John C. Breckinridge | Southern Democratic | 0 | 218 | 0.5% |
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