United States presidential election in Oklahoma, 1948

United States presidential election in Oklahoma, 1948
Oklahoma
November 2, 1948
 
Nominee Harry S. Truman Thomas E. Dewey
Party Democratic Republican
Home state Missouri New York
Running mate Alben W. Barkley Earl Warren
Electoral vote 10 0
Popular vote 452,782 268,817
Percentage 62.75% 37.25%

The 1948 United States presidential election in Oklahoma took place on November 2, 1948. All 48 states were part of the 1948 United States presidential election. Oklahoma voters chose 10 electors to the Electoral College, who voted for President and Vice President.

Incumbent President Harry S. Truman won Oklahoma by a landslide 25.5% margin of victory.[1] Oklahoma was a reliably Democratic state, with the party nominee winning 10 out of the first 15 elections held in the state. In 1964, Lyndon Johnson became the next and last Democratic presidential candidate to carry the state.[2]

United States presidential election in Oklahoma, 1948[3]
Party Candidate Votes Percentage Electoral votes
Democratic Harry S. Truman 452,782 62.75% 7
Republican Thomas E. Dewey 268,817 37.25% 0
Totals 721,599 100.0% 10

References

  1. ↑ "1948 Presidential General Election Results - Oklahoma". uselectionatlas.org.
  2. ↑ Gust, Steve (October 6, 2012). "Oklahoma student who attended Democratic National Convention anticipates lifetime in politics". The Oklahoman. Retrieved November 9, 2016.
  3. ↑ "1948 Presidential Election Results - Oklahoma". Dave Leip's U.S. Election Atlas. Retrieved November 9, 2016.
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