United States presidential election in Missouri, 1840
Main article: United States presidential election, 1840
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Elections in Missouri | ||||||||||||||||
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The 1840 United States presidential election in Missouri took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
Missouri voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Missouri by a margin of 13.26%.
Results
United States presidential election in Missouri, 1840[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Martin Van Buren of New York | Richard M. Johnson of Kentucky | 29,969 | 56.63% | 4 | 100.00% | ||
Whig | William Henry Harrison of Ohio | John Tyler of Virginia | 22,954 | 43.37% | 0 | 0.00% | ||
Total | 52,923 | 100.00% | 4 | 100.00% | ||||
References
- ↑ "1840 Presidential General Election Results - Missouri". U.S. Election Atlas. Retrieved 23 December 2013.
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