United States presidential election in Louisiana, 1988

United States presidential election in Louisiana,1988
Louisiana
November 8, 1988
 
Nominee George H.W. Bush Michael Dukakis
Party Republican Democratic
Home state Texas Massachusetts
Running mate Dan Quayle Lloyd Bentsen
Electoral vote 10 0
Popular vote 883,702 717,460
Percentage 54.3% 44.1%

County Results
  Dukakis—60-70%
  Dukakis—50-60%
  Dukakis—<50%
  Bush—<50%
  Bush—50-60%
  Bush—60-70%
  Bush—70-80%
President before election

Ronald Reagan
Republican

 Elected President

George H.W. Bush
Republican

Bush at the 1988 Republican National Convention, in New Orleans.


The 1988 United States presidential election in Louisiana took place on November 8, 1988 throughout all 50 states and D.C., which was part of the 1988 United States presidential election. Voters chose 10 representatives, or electors to the Electoral College, who voted for President and Vice President.

Louisiana strongly voted for the Republican nominee, Vice President George H. W. Bush, over the Democratic nominee, Massachusetts governor Michael Dukakis. The margin was 10%, which was the closest southern state margin, and the best Southern state showing for Dukakis.

Results

United States presidential election in Louisiana, 1988[1]
Party Candidate Votes Percentage Electoral votes
Republican George H. W. Bush 883,702 54.27% 10
Democratic Michael Dukakis 717,460 44.06% 0
America First David Duke 18,612 1.14% 0
Libertarian Ron Paul 4,115 0.25% 0
New Alliance Lenora Fulani 2,355 0.14% 0
Democrats for Economic Recovery Lyndon LaRouche 1,958 0.12% 0
Invalid or blank votes —
Totals 1,628,202 100.00% 10
Voter turnout —

References

  1. ↑ "1988 Presidential General Election Results - Louisiana". Dave Leip's U.S. Election Atlas. Retrieved 2008-08-25.
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