Zarembo Island
Zarembo Island is an island in the Alexander Archipelago of southeastern Alaska, United States. It lies directly south of Mitkof Island and northwest of Etolin Island. To the northwest is Kupreanof Island and to the southwest is Prince of Wales Island. It has a land area of 183.14 square miles (474.330 square kilometres), making it the 34th largest island in the United States. It has no permanent resident population. It was first charted in 1793 by James Johnstone, one of George Vancouver’s officers during his 1791-95 expedition. He only charted its north, west, and south coasts, not realizing it was an island.[1] The island is named after Dionizy Zaremba, a Polish employee of the Russian American Company and explorer of Alaska. Usually known as Dionysius Zarembo, he was Commander of the RAC ship Chichagof during the foundation of the Redoubt San Dionisio, named for his name-saint, a fortification at present-day Wrangell which was established to forestall encroachment of the Stikine region by the Hudson's Bay Company.
References
- ↑ Vancouver, George, and John Vancouver (1801). A voyage of discovery to the North Pacific ocean, and round the world. London: J. Stockdale.
- Zarembo Island: Block 1037, Census Tract 3, Wrangell-Petersburg Census Area, Alaska United States Census Bureau
- Wrangell, Alaska webpage
- U.S. Geological Survey Geographic Names Information System: Zarembo Island
Coordinates: 56°21′21″N 132°50′09″W / 56.35583°N 132.83583°W